Question

The ages of leena and heena are in the ratio of 5: 3 Ten years hence, the ratio of their age will be 7:5. Find then present ages​

Answer 1

$\bf{\red{Answer}}$

Given that:-

The ages of Leena and Heena are in the ratio of 5: 3 .

Ten years hence, the ratio of their age will be 7:5.

Present Age = ?

$\boxed{\sf{Let's \ Find \ out! }}$

Let the age constant be x.

So Leena's age is 5x and Heena, 3x

Ten years hence:-

$\sf{\dfrac{5x+10}{3x+10} = \dfrac{7}{5}}$

$\sf{5(5x+10) = 7(3x+10)}$

$\sf{25x+50 = 21x+70}$

$\sf{25x-21x = -50+70}$

$\sf{4x = 20}$

$\huge{\boxed{\sf{x = 5}}}$

Now, we will multiply x with 5 to find Leena's age

= 5 × 5 = 25 years

Now, we will multiply x with 3 to find Heena's age.

= 3 × 5 = 15 years.

So, Leena and Heena's ages are 25 and 15 years respectively .