The ages of Leena and heena are in the ratio of 7:5. ten years hence, the ratio of their ages will be 9:7. find the present ages.
Answers
Answer:
LEENA'S AGE IS 35 AND HEENA'S AGE IS 25
Step-by-step explanation:
Ratio = 7 : 5
Let their ages be 7m and 5m respectively
7m + 10 : 5m + 10 :: 9: 7
7(7m+ 10) = 9(5m + 10) [Product of means = Product of extremes]
49m + 70 = 45m + 90
49m - 45 m = 90 - 70
4m = 20
m = 20/4 = 5
LEENA AGE = 5 X 7 = 35
HEENA AGE = 5 X 5 = 25
PLS MARKS AS BRAINLIEST
Given :
- The ages of Leena and heena are in the ratio of 7:5.
- Ten years hence, the ratio of their ages will be 9:7
To Find :
- Thier present ages.
Solution :
Assume that the present ages of Leena and heena are 7x and 5x respectively.
As per the condition given in question after 10 year
- ➡ Leena's age = ( 7x + 10 )
- ➡ Heena's age = ( 5x + 10 )
We also know that after Ten years the ratio of their ages will be 9:7.
How to solve ?
We have First find out the value of x and after finding value of x we have to value of x in
7x to find Leena's age and in 5x to find Heena's age
So ,
- By cross multiplication ❌
- Here we get the value of x so place this value in 7 x and 5 x
Therefore ,
➡Leena's Present age
= 7 x = 7 × (5)
- 35 years
➡Heena's Present age
= 5x = 5 × (5)
- 25 years