Question

The ages of leena and hina are in the ratio 7:5. Ten years hence , the ratio
of their ages will be 9:7. Find their present ages.

Answer 1

Answer:

Leena :Hena = 7:5

Leena = 7k

Hena= 5k

After 10 years

LEENA =7k+10

HENA= 5k+10

RATIO = 7k+10/5k+10 =9/7

49k+70 = 45k+90

4k=20

K=5

So their present ages are

leena = 35 years

Hena= 25 years

Answer 2

Answer:

The Present ages are -

• Leena = 35 years
• Heena = 25 years

Step-by-step explanation:

Given :

Ages of Leena and Heena are in Ratio = 7 : 5

Ratio after 10 Years = 9 : 7

To Find :

Their present Ages

Solution :

Let the present Ages be -

• Leena as 7x
• Heena as 5x

$\rule{300}{1.5}$

➡ (7x + 10)/(5x + 10) = 9/7

➡ 7(7x + 10) = 9(5x + 10)

➡ 49x + 70 = 45x + 90

➡ 49x - 45x = 90 - 70

➡ 4x = 20

➡ x = 20/4

➡ x = 5

$\rule{300}{1.5}$

Heena's age =

➡ 5 × 5

➡ 25

$\rule{300}{1.5}$

Leena's age =

➡ 7 × 5

➡ 35

$\therefore$ The Present ages are -

• Leena = 35 years
• Heena = 25 years