Question

The ages of Leena the ages of Leena and Heena are in the ratio of 7 ratio 5 10 years hence the ratio of their ages will be 9 ratio 7 find their present age

Answer 1

Let the present ages of Leena and Heena be 7x and 5x respectively.

After 10 years = $\frac{7x + 10}{5x + 10}$ = $\frac{9}{7}$

⇒ 7(7x + 10) = 9( 5x + 10) (By cross multiplication)

⇒ 49x + 70 = 45x + 90

⇒ 4x = 20

⇒ x=5

Hence the present age of Leena, 7x = 7*5

= 35

Present age of Heena, 5x = 5*5

= 25

Answer 2

Answer:

The Present ages are -

• Leena = 35 years
• Heena = 25 years

Step-by-step explanation:

Given :

Ages of Leena and Heena are in Ratio = 7 : 5

Ratio after 10 Years = 9 : 7

To Find :

Their present Ages

Solution :

Let the present Ages be -

• Leena as 7x
• Heena as 5x

$\rule{300}{1.5}$

➡ (7x + 10)/(5x + 10) = 9/7

➡ 7(7x + 10) = 9(5x + 10)

➡ 49x + 70 = 45x + 90

➡ 49x - 45x = 90 - 70

➡ 4x = 20

➡ x = 20/4

➡ x = 5

$\rule{300}{1.5}$

Heena's age =

➡ 5 × 5

➡ 25

$\rule{300}{1.5}$

Leena's age =

➡ 7 × 5

➡ 35

$\therefore$ The Present ages are -

• Leena = 35 years
• Heena = 25 years