Question

The
ages
of
my father, mother, elder brother and younger sister are 42, 36, 12 and 6 years
respectively. If I am 9 years old, find the average of our ages.​

Answer 1

Appropriate question ::-

The ages of my father, mother, elder brother and younger sister are 42, 36, 12 and 6 years respectively. If I am 9 years old, find the average of our ages.

Given ::-

• Age of father = 42 yrs.

• Age of mother = 36 yrs.

• Age of elder brother = 12 yrs.

• Age of younger sister = 6 yrs.

• Age of her = 9 yrs.

To find ::-

• Average of their ages ?

Solution ::-

• Ages are ::- 42, 36, 12 , 6 and 9 years.

Now we will add all of their ages ::-

• 42 + 36 + 12 + 6 + 9

• 105

Now we will divide it by 5

• $\dfrac{105}{5}$

• 21

_________

So , The average of their ages is 21

Answer 2

Answer:

21

Step-by-step explanation:

formula of avreage =$\frac{sum of all constants}{number of constants}$=$\frac{42+36+12+6+9}{5}$=$\frac{105}{5}$

∴ average = 21