Math, asked by guptapriyanka9368, 7 months ago

The ages of Nirav and his mother is is in the ratio 1:2 . 10 years ago their ages were in the ratio 1:3. What is the present age of Nirav​

Answers

Answered by Anonymous
29

Answer:

Present age of Nirav is 20 years.

Step-by-step explanation:

Given :-

  • The ages of Nirav and his mother is in the ratio 1:2.
  • 10 years ago, their ages were in the ratio 1:3.

To find :-

  • The present age of Nirav.

Solution :-

Consider,

  • Present age of Nirav = x years
  • Present age of his mother = 2x years

10 years ago, their ages were in the ratio 1:3.

10 years ago,

  • Age of Nirav = (x-10) years
  • Age of his mother = (2x-10) years

According to the question ,

\implies\sf{(x-10):(2x-10)=1:3}

\implies\sf{\dfrac{x-10}{2x-10}=\dfrac{1}{3}}

\implies\sf{3x-30=2x-10}

\implies\sf{3x-2x=-10+30}

\implies\sf{x=20}

★ Present age of Nirav = 20 years

★ Present age of his mother = 2×20 = 40 years.

Answered by Anonymous
27

Step-by-step explanation:

Assume that the age of Nirav is 1x and his mother is 2x.

10 years ago their ages were in the ratio 1:3.

10 years ago:

  • Age of Nirav = (x - 10) years
  • Age of his mother = (2x - 10) years

As per given condition,

→ (x - 10)/(2x - 10) = 1/3

→ 3(x - 10) = 2x - 10

→ 3x - 30 = 2x - 10

→ x = 20

Hence, present age of:

  • Nirav = x = 20 years
  • Mother = 2x = 2(20) = 40 years
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