Question

The ages of Nirav and his mother is is in the ratio 1:2 . 10 years ago their ages were in the ratio 1:3. What is the present age of Nirav​

Answer 1

Answer:

Present age of Nirav is 20 years.

Explanation:

Given :-

• The ages of Nirav and his mother is in the ratio 1:2.
• 10 years ago, their ages were in the ratio 1:3.

To find :-

• Present age of Nirav.

Solution :-

Let the present age of Nirav be x years and the present age of his mother be 2x years.

10 years ago,

• Age of Nirav = (x-10) years
• Age of his mother = (2x-10) years

According to the question,

(x-10):(2x-10) = 1:3

→ $\sf{\dfrac{x-10}{2x-10}=\dfrac{1}{3}}$

→ 3x-30=2x-10

→ 3x-2x = -10+30

→ x = 20

Therefore,

• Present age of Nirav = 20 years.
• Present age of his mother = (2×20) = 40 years.

Answer 2

Solution :

$\underline{\bf{Given\::}}$

The age of Nirav & his mother is in the ratio 1:2. Ten years ago their ages were in the ratio 1:3.

$\underline{\bf{Explanation\::}}$

Firstly, we suppose the given ratio be r;

The present age of Nirav be r & the present age of mother be 2r respectively;

$\underbrace{\bf{10\:years\:ago\::}}}}$

The age of Nirav was (r-10) years.

The age of Mother was (2r-10) years.

A/q

$\mapsto\sf{\dfrac{r-10}{2r-10} =\dfrac{1}{3} }\\\\\mapsto\sf{3(r-10) = 1(2r-10)}\\\\\mapsto\sf{3r -30 = 2r - 10}\\\\\mapsto\sf{3r -2r = -10 + 30}\\\\\mapsto\bf{r = 20\:years}$

Thus;

The present age of Nirav is r = 20 years

The present age of Mother is 2r = 2 × 20 = 40 years .