Question

The ages of Ravi and Rohit are in the ratio 5:7 . Eight years ago , their ages were in the ratio 7:13 . Find their present ages .

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Answer 1

Answer:

Let the present age of Ravi and Rohit be

5x and 7x respectively.

ATQ

5x-8/7x-8 = 7/13

by cross multiply we get

13(5x-8) = 7(7x-8)

65x -104 = 49x -56

65x-49x = -56+104

16x = 48

X = 48/16

X = 3

Now

Present age of Ravi = 5x = 5×3 = 15year

and present age of Rohit = 7x = 7×3 = 21year

Answer 2

Answer:

Let age of A and B be 5x and 7x respectively.

According to the question-

7x−8

5x−8

​

=  

13

7

​

 

13(5x−8)=7(7x−8)

65x−104=49x−56

⇒65x−49x=104−56

⇒x=  

16

48

​

=3

Therefore,

Present age of A=5×3=15 years

Present age of B=7×3=21 years

Step-by-step explanation: