The
ages of Reema and Mehul are in the ratio 6:6. Four years later the sum of their ages will be 44 years.
What are their present ages?
Answers
Let the current age of Rahul and Haroon be 5x and 7x respectively
Four years later their ages become 5x + 4 and 7x + 4 respectively.
According to the question,
5x + 4 +7x + 4 = 56
or 12x + 8 = 56
Transposing 8 to the RHS we get,
12x = 48
Dividing both sides by 12 gives,
x = 48/12 = 4
Thus current age of Rahul = 5*4 = 20
Haroon = 7*4 = 28
Answer:
Reema's age = 18
Mehul's age = 18
Step-by-step explanation:
According to the question
The ratio of ages = 6:6
so,
Reema's age four years later = 6x+4
Mehul's age four years later = 6x+4
As sum of ages = 44
We have to add the ages of both
their present ages =6x+4 + 6x+4 = 44
(adding the like terms)
6x+6x+4+4=44
12x+8=44
12x=44-4
12x=36
x=36/12
x=3
Now,
Reema's present age = 6x = 6×3 = 18
Mehul's present age = 6x = 6×3 = 18