Question

the ages of reena and meena are in the ratio 3:4.Eight years from now their ages will be 5:6.Find their present ages?

Answer 1

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$</p><p>\underline {\underline {\orange{Step-By-Step-Explaination \: : }}}$

The ratio is the present ages is Reena and Meena is 3:4.

The ratio is the present ages is Reena and Meena is 3:4.Let their ages be 3x and 4x respectively.

The ratio is the present ages is Reena and Meena is 3:4.Let their ages be 3x and 4x respectively.After 8 years, the reaction of their ages will be 5:6.

The ratio is the present ages is Reena and Meena is 3:4.Let their ages be 3x and 4x respectively.After 8 years, the reaction of their ages will be 5:6.Hence,

$\frac{3x + 8}{4x + 8} = \frac{5}{6}$

Cross Multiplying,

$6(3x + 8) = 5(4x + 8)$

$18x + 48 = 20x + 32$

$2x = 16 \\ \\ x = 8$

Hence, Age of Reena = 3x = 24 years.

Hence, Age of Reena = 3x = 24 years.Age of Meena = 4x = 32 years.

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Answer 2

Step-by-step explanation:

Given:

• Age of Reena and Meena are in ratio 3:4
• After 8 years their ages will be 5:6

To Find:

• Present ages of Reena and Meena

Solution: Let the present ages of Reena and Meena be 3x and 4x

† After 8 years their ages will be †

• 3x + 8 ( Reena's age )
• 4x + 8 ( Meena's age )

A/q After 8 years their ages will be in ratio 5:6

3x + 8 = 5

4x + 8 = 6

$\small\implies{\sf }$ 18x + 48 = 20x + 40 ( Cross Multiplication )

$\small\implies{\sf }$ 48 – 40 = 20x – 18x

$\small\implies{\sf }$ 8 = 2x

$\small\implies{\sf }$ 8/2 = x

$\small\implies{\sf }$ 4 = x

So, Their present ages are :

★ Reena's age = 3x = 3 (4) = 12 Years ★

★ Meena's age = 4x = 4(4) = 16 Years ★