Math, asked by sumangupta7055, 1 year ago

The ages of Rohit and Mohit is in ratio of
9:10.if 6 years ago, sum of their ages was 45 years then find the present age of Rohit.​


Anonymous: hiii

Answers

Answered by Anonymous
1

Hey!!!

the ratio of the present ages of rohit and mohit is 9:10.

let their present age be 9x and 10x

6 yrs ago, the sum of their age was 45

therefore 9x - 6 + 10x - 6 = 45 yrs

>> 19x - 12 = 45 yrs

>> 19x = 45 + 12

>> 19x = 57

>> x = 57/19

>> x = 3

hence, present age of Rohit = 9x = 9 × 3 = 27 yrs

present age of Mohit = 10x = 10 × 3 = 30 yrs

cheers!!!


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