Question

The ages of Seema and Babita are in the ratio of 5:7 . If Seema were 9 years older and Babita 9 years younger, the age of Seema would have been twice the age of Babita. Find their ages.

Answer 1

Answer:

let their age be 5x and 7x.

5x + 9 = 2(7x - 9)

5x + 9 = 14x - 18

9 + 18 = 14x - 5x

27 = 9x

x = 27/9

x = 3

seema' s age = 5 × 3

15 years

babita' s age = 7 × 3

21 years