Math, asked by achalak422, 5 months ago

The ages of Seeta and Geeta are in the ratio 5:2. After 3 years, Seeta will be twice as old as Geeta. Find their present ages.​

Answers

Answered by nuzhat9818
4

Mark as the brainliest!

Attachments:
Answered by Anonymous
53

\large{\underline{\sf{\red{Required\:Answer:}}}}

  • Seeta's age = 15 years

  • Geeta's age = 6 years.

Given:-

  • The ages of Seeta and Geeta are in the ratio 5:2.

  • After 3 years, Seeta will be twice as old as Geeta.

To Find:-

  • Their present ages.

Solution:-

  • Let the age of Sita and Gita be 5x years and 2x years.

After 3 years,

  • Seeta's age = (5x + 3) years.

  • Geeta's age = (2x + 3) years.

According to the Question :-

\pink{\implies\:\:} \rm{5x+3=(2x+3)2 }

\pink{\implies\:\:} \rm{5x+3=4x+6 }

\pink{\implies\:\:} \rm{5x-4x=6-3 }

\pink{\implies\:\:} \rm{x=3 }

\purple{\star\:\:} Seeta's age = 5x years.

\green{\implies\:\:} \rm{5\times 3 }

\green{\implies\:\:} \rm{15\: years}

\purple{\star\:\:} Geeta's age = 2x years.

\orange{\implies\:\:} \rm{2\times 3}

\orange{\implies\:\:} \rm{6\: years}

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