The ages of Seeta and Geeta are in the ratio 5:2. After 3 years, Seeta will be twice as old as Geeta. Find their present ages.
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• Seeta’s age = 15 years
• Geeta’s age = 6 years
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Step by step explanation-:
Let the age of Seeta and Geeta be 5x
and 2x years.
After 3 years -:
Seeta’s age = (5x + 3)
Geeta’s age = (2x + 3)
According to question-:
5x + 3 = (2x + 3) 2
5x + 3 = 4x + 6
5x - 4x = 6 - 4
x = 3
• Seeta’s age = 5x
5 x 3
= 15 years
• Geeta’s age = 2x
2 x 3
=6 years
______________________________
• Seeta’s age = 15 years
• Geeta’s age = 6 years
______________________________
Step by step explanation-:
Let the age of Seeta and Geeta be 5x
and 2x years.
After 3 years -:
Seeta’s age = (5x + 3)
Geeta’s age = (2x + 3)
According to question-:
5x + 3 = (2x + 3) 2
5x + 3 = 4x + 6
5x - 4x = 6 - 4
x = 3
• Seeta’s age = 5x
5 x 3
= 15 years
• Geeta’s age = 2x
2 x 3
=6 years
______________________________
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