Question

The ages of Sita and her sister are in ratio 3:8. After 12 years the ratio of their ages is 7:8. Find their present ages.​

Answer 1

Answer:

Step-by-step explanation:

Present ages,

that of sita is 3x and that of gita is 8x.

After 12 years,

Sita is 3x + 10 and gita is 8x + 10.

So age of sita is 3x + 10 = 7x

thus, x = 5 .

Present ages of sita is 35 and that of gita is 25

Answer 2

Answer:

32,48 yrs

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Step-by-step explanation:

Let present ages of A and B are 2x years and 3x years respectively. After 12 yrs

their ages are (2x+12)years and (3x+12)years respectively , acordingly:-

(2x+12)/(3x+12)= 11/15

or. 33x+132 = 30x+180

or. 3x= 48 => x=48/3 = 16

Present ages of:-

A=2.x =2×16 = 32yrs. and B =3.x =3×16 = 48 yrs.

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