Math, asked by sun96775, 10 months ago

the ages of sona and Sonali are in the ratio 5 ratio 3 five year hence the ratio of their ages will be 10 ratio 7 find their present ages

Answers

Answered by Anonymous
11

Answer:

hiii

your answer is here !

Step-by-step explanation:

let the present age of sona be 5x & Sonali be 3y .

after 5 years

sona age be = 5x+5

Sonali age be = 3x+5

5x+5/3x+5 = 10/7

7(5x+5) = 10(3x+5)

35x+35=30x+50

35x-30x= 50-35

5x=15

x= 15/5

x= 3

present age of sona = 5x=5×3=15 years

present age of Sonali=3x= 3×3=9years

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Answered by Sauron
21

Answer:

The present ages are Sona is 15 years old and Sonali is 9 years old.

Step-by-step explanation:

Given :

Ratio of Sona and Sonali = 5 : 3

Ratio of ages after 5 years = 10 : 7

To find :

Their present ages

Solution :

Let the present ages be -

  • Sona as 5y
  • Sonali as 3y

Ages after 5 years -

  • Sona = 5y + 5
  • Sonali = 3y + 5

\sf{\longrightarrow} \: {\dfrac{5y + 5}{3y + 5}  =  \dfrac{10}{7}}  \\  \\ \sf{\longrightarrow} \:7(5y + 5) = 10(3y + 5) \\  \\ \sf{\longrightarrow} \:35y + 35 = 30y + 50 \\  \\ \sf{\longrightarrow} \:35y - 30y = 50 - 35 \\  \\ \sf{\longrightarrow} \:5y = 15 \\  \\ \sf{\longrightarrow} \:y =  \dfrac{15}{5}  \\  \\ \sf{\longrightarrow} \:y = 3

\rule{300}{1.5}

Sona's present age -

\sf{\longrightarrow} \:5(3) \\  \\ \sf{\longrightarrow} \:15

Sona is presently 15 years old.

\rule{300}{1.5}

Sonali's present age -

\sf{\longrightarrow} \:3(3) \\  \\ \sf{\longrightarrow} \:9

Sonali is presently 9 years old.

\therefore The present ages are Sona is 15 years old and Sonali is 9 years old.

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