Math, asked by bichchu, 1 year ago

The ages of sonal and manoj are in the ratio of 7:5.ten years since the ratio of their ages will be 7:5. Find their present age.

Answers

Answered by ls6436736
25

Step-by-step explanation:

Given,

The ratio of present ages of Sonal and Manoj =7:5

Let the age of Sonal be 7x and age of Manoj be 5x.

10 years later their age will be (7x+10) and (5x+10).

Given,

The ratio of ages after 10 years=9:7

So, now, assume the ages be 9x and 7x.

=7x+10+5x+10=9x+7x

=12x-16x. =-10-10

=-4 =-20

=-4x =-20

=x =-20/-4

=x =5

So, the present age of Sonal=7x=7×5=35years.

And the present age of Manoj=5x=5×5=25 years.

Hope this answer will help you.

Answered by prasantmajhi100
0

Step-by-step explanation:

Given,

The ratio of present ages of Sonal and Manoj =7:5

Let the age of Sonal be 7x and age of Manoj be 5x.

10 years later their age will be (7x+10) and (5x+10).

Given,

The ratio of ages after 10 years=9:7

So, now, assume the ages be 9x and 7x.

=7x+10+5x+10=9x+7x

=12x-16x. =-10-10

=-4 =-20

=-4x =-20

=x =-20/-4

=x =5

So, the present age of Sonal=7x=7×5=35years.

And the present age of Manoj=5x=5×5=25 years.

Hope this answer will help you.

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