Question

The ages of Sonu and monu are in ratio 5:7. if 9 years ago,the age of Sonu would have been twice the age of monu.find their ages​

Answer 1

$\boxed{\red{AnswEr:-}}$

➟ The ages of Sonu and Monu are respectively 15 years and 21 years.

*Question :

• The ages of Sonu and monu are in ratio 5:7. if 9 years ago,the age of Monu would have been twice the age of Sonu.Find their ages. *(There's a little mistake in given question. It has been corrected here.)

★ GivEn :-

• The ages of Sonu and monu are in ratio 5:7.
• 9 years ago,the age of Monu would have been twice the age of Sonu.

★ To FinD :-

• Ages of Sonu and Monu.

★ SolutiOn :-

➟ The ratio of ages of Sonu and Monu is 5 : 7.

➟ Let the common factor of the ratio be x (x > 0 )

➟ So, the age of Sonu is 5x years and the age of Monu is 7x years.

➟ 9 years ago, the age of Sonu would be ( 5x - 9 ) years and the age of Monu would be ( 7x - 9 ) years.

➟ According to the given question,

9 years ago the age of Monu would be twice the age of Sonu.

➟ Therefore,

$2(5x - 9) = 7x - 9 \\ \\ = > 10x - 18 = 7x - 9 \\ \\ = > 10x - 7x = - 9 + 18 \\ \\ = > 3x = 9 \\ \\ = > x = \frac{9}{3} = 3$

$\therefore$ The age of Sonu is = (5 × 3) = 15 years.

And the age of Monu is = (7 × 3) = 21 years.

★ VerificatiOn :-

➟ The ratio of the ages of Sonu and Monu is 15 : 21 = 5 : 7.

➟ 9 years ago, the age of Sonu would be = ( 15 - 9 ) = 6 years and the age of Monu would be = ( 21 - 9 ) = 12 years.

➟ Therefore, The age (9 years ago) of Monu is twice [( 12 ÷ 6 ) = 2 ] than Sonu.

➟ Hence, It is verified.

Answer 2

Answer:

$\boxed{\red{AnswEr:-}}$

➟ The ages of Sonu and Monu are respectively 15 years and 21 years.

*Question :

The ages of Sonu and monu are in ratio 5:7. if 9 years ago,the age of Monu would have been twice the age of Sonu.Find their ages. *(There's a little mistake in given question. It has been corrected here.)

★ GivEn :-

The ages of Sonu and monu are in ratio 5:7.

9 years ago,the age of Monu would have been twice the age of Sonu.

★ To FinD :-

Ages of Sonu and Monu.

★ SolutiOn :-

➟ The ratio of ages of Sonu and Monu is 5 : 7.

➟ Let the common factor of the ratio be x (x > 0 )

➟ So, the age of Sonu is 5x years and the age of Monu is 7x years.

➟ 9 years ago, the age of Sonu would be ( 5x - 9 ) years and the age of Monu would be ( 7x - 9 ) years.

➟ According to the given question,

9 years ago the age of Monu would be twice the age of Sonu.

➟ Therefore,

$\begin{gathered}2(5x - 9) = 7x - 9 \\ \\ = > 10x - 18 = 7x - 9 \\ \\ = > 10x - 7x = - 9 + 18 \\ \\ = > 3x = 9 \\ \\ = > x = \frac{9}{3} = 3\end{gathered}$

$\therefore∴ The age of Sonu is = (5 × 3) = 15 years.$

And the age of Monu is = (7 × 3) = 21 years.

★ VerificatiOn :-

➟ The ratio of the ages of Sonu and Monu is 15 : 21 = 5 : 7.

➟ 9 years ago, the age of Sonu would be = ( 15 - 9 ) = 6 years and the age of Monu would be = ( 21 - 9 ) = 12 years.

➟ Therefore, The age (9 years ago) of Monu is twice [( 12 ÷ 6 ) = 2 ] than Sonu.

➟ Hence, It is verified.