Question

The ages of Sonu and monu are in ratio 5:7. if 9 years ago,the age of Sonu would have been twice the age of monu.find their ages​

Answer 1

Answer:

As the present ages of Sonu and Monu are in ratio 5:7, let their present ages be 5x years and 7x years respectively.

Before 9 years,

the age of Monu would have been (7x-9) years and the age of Sonu would have been 2(7x-9) years that is (5x-9) years.

According to the condition,

2(7x-9)=(5x-9)

=> 14x-5=18-9

=> 9x=9

=> x= 1.

So, the present age of Sonu is 5 years and the present age of Monu is 7 years. (Answer)

Hope it works.

Answer 2

AnswEr :

Ratio of the ages of Sonu & Monu is 5: 7.

Let's consider that age of Sonu be 5x

And, age of Monu be 7x.

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⠀⠀⠀⠀⠀⠀ $\underline{\boldsymbol{According\: to \:the\: Question :}}$

Sonu's age was twice the age of monu nine years ago. {Given}

$\implies\sf 5x - 9 = 2(7x - 9)\qquad\bigg\lgroup\bf Subtracting \ 9 \ from \ both's \ age \bigg\rgroup \\\\\\:\implies\sf 5x - 9 = 14x - 18 \\\\\\:\implies\sf 5x - 14x = 9 - 18 \\\\\\:\implies\sf - 9x = - 9 \\\\\\:\implies\sf x = \dfrac{\cancel{-9}}{\cancel{-9}} \\\\\\:\implies\boxed{\frak{\pink{x = 1}}}$

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Substituting value of the x in Sonu & Monu's age, we get :

$:\implies\sf Sonu's \ age = 5x \\\\\\:\implies\sf Sonu's \ age = 5(1) \\\\\\:\implies\boxed{\frak{\purple{Sonu's \ age = 5 \ years}}}$

$:\implies\sf Monu's \ age = 7x \\\\\\:\implies\sf Monu's \ age = 7(1) \\\\\\:\implies\boxed{\frak{\purple{ Monu's \ age = 7 \ years }}}$

$\therefore$ Hence, Age of Sonu & Monu is 5 years & 7 years.