The ages of Sonu and monu are in ratio 5:7. if 9 years ago,the age of Sonu would have been twice the age of monu.find their ages
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Answers
Answer:
Step-by-step explanation:
ANSWER:-
Given that:-
- Ages of Sonu and Monu are in ratio 5:7
- Let the constant of ratio be taken as x.
- So age of Sonu is 5x
- And age of Monu is 7x.
Case given in the question:-
- Before 9 years,
- Age of Sonu was twice the age of Monu.
Note:-
- Always consider a ratio constant as x.
- This helps to make equations easier.
- In this, always assume the opposite of what the case is given.
- For example twice was given in respect of Sonu but the equation has been made with respect to Monu.
- Ago depicts the earlier age, so subtraction follows.
✴ The ages of Sonu and monu are in ratio 5:7. If 9 years ago,the age of Sonu would have been twice the age of monu. Find their ages .
✒ The present ages of Sonu is 7 years and Monu is 5 years.
- The ages of Sonu and monu are in ratio 5:7.
- 9 years ago,the age of Sonu would have been twice the age of monu.
____________________________
- The present ages of Sonu and Monu.
____________________________
Let the present age from x .
According to the question,
⭐ The ages of Sonu and monu are in
ratio 5:7.
- The present age of Monu = 5x
- The present age of Sonu = 7x
⭐ 9 years ago,the age of Sonu would have been twice the age of monu.
- 9 years ago Monu's age = 5x - 9
- Monu's age 9 years younger = 7x-9
According to the given condition;
Our equation will be => 5x - 9 = 2 (7x -9 )
Solving ; 5x - 9 = 2 ( 7x - 9 )
➝ 5x - 9 = 2 ( 7x - 9 )
➝ 5x - 9 = 14 x - 18
➝ 5x - 14x = - 18 + 9
➝ 9 x = 9
➝ x =
➝ x = 1
We Considered;
- The present age of Monu
=> 5x = 5 × 1 = 5 years
- The present age of Sonu
=> 7x = 7 × 1 = 7 years.
➡ Hence, Now Monu is 5 years old & Sonu is 7 years old.
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