Math, asked by kqran, 1 year ago

the ages of Sonu and Monu are in ratio 7 ratio 5 10 years hence the ratio of their ages will be 9 ratio 7 find their present ages

Answers

Answered by Ayush995
5
let sonu and monu age be 7x and 5x
a/q
(7x+10)/(5x+10)=9/7
7(7x+10)=9(5x+10)
49x+70=45x+90
49x-45x=90-70
4x=20
x=20/4=5


Present age of sonu=5*7=35yrs
monu=5*5=25yrs
Answered by Sauron
6

Answer:

The Present ages are -

Sonu = 35 years

Monu = 25 years

Step-by-step explanation:

Given :

Ages of Sonu and Monu are in Ratio = 7 : 5

Ratio after 10 Years = 9 : 7

To Find :

Their present Ages

Solution :

Let the present Ages be -

  • Sonu as 7x
  • Monu as 5x

\rule{300}{1.5}

➡ (7x + 10)/(5x + 10) = 9/7

➡ 7(7x + 10) = 9(5x + 10)

➡ 49x + 70 = 45x + 90

➡ 49x - 45x = 90 - 70

➡ 4x = 20

➡ x = 20/4

➡ x = 5

\rule{300}{1.5}

Sonu's age =

➡ 5 × 5

➡ 25

\rule{300}{1.5}

Monu's age =

➡ 7 × 5

➡ 35

\therefore The Present ages are -

  • Sonu = 35 years
  • Monu = 25 years
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