Math, asked by Dharmendrajain, 6 months ago

the ages of Sonu and monu are in the ratio 5.7 If 9years ago, the age of Sonu would have been twice the age of monu. find the ages

Answers

Answered by amansharma264
17

EXPLANATION.

  • GIVEN

The age of sonu and monu are in the ratio

=> 5:7

9 years ago,the age of sonu would have

been twice the age of monu.

FIND THE AGES.

According to the question,

Let the age of sonu be = 5x

Let the age of monu be = 7x

=> 9 years ago, the age of sonu would

have been twice the age of monu.

=> Sonu age be = 5x - 9

=> monu age be = 7x - 9

=> 5x - 9 = 2 ( 7x - 9 )

=> 5x - 9 = 14x - 18

=> 9 = 9x

=> x = 1

Therefore,

sonu ages = 5x = 5 years.

monu ages = 7x = 7 years.

Answered by Anonymous
28

Answer:

Age of Sonu is 5 years and Monu is 7 years

Step-by-step explanation:

The ages of Sonu and monu are in the ratio 5:7.

Assume that the age of Sonu he 5x and Monu be 7x.

9 years ago, the age of Sonu would have been twice the age of Monu.

9 years ago:

  • Age of Sonu = (5x - 9) years
  • Age of Monu = (7x - 9) years

As per given condition,

→ 5x - 9 = 2(7x - 9)

→ 5x - 9 = 14x - 18

→ 14x - 5x = - 9 + 18

→ 9x = 9

→ x = 1

Hence, the present age of

  • Sonu = 5x = 5(1) = 5 years
  • Monu = 7x = 7(1) = 7 years
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