the ages of Sonu and monu are in the ratio 5.7 If 9years ago, the age of Sonu would have been twice the age of monu. find the ages
Answers
Answered by
17
EXPLANATION.
- GIVEN
The age of sonu and monu are in the ratio
=> 5:7
9 years ago,the age of sonu would have
been twice the age of monu.
FIND THE AGES.
According to the question,
Let the age of sonu be = 5x
Let the age of monu be = 7x
=> 9 years ago, the age of sonu would
have been twice the age of monu.
=> Sonu age be = 5x - 9
=> monu age be = 7x - 9
=> 5x - 9 = 2 ( 7x - 9 )
=> 5x - 9 = 14x - 18
=> 9 = 9x
=> x = 1
Therefore,
sonu ages = 5x = 5 years.
monu ages = 7x = 7 years.
Answered by
28
Answer:
Age of Sonu is 5 years and Monu is 7 years
Step-by-step explanation:
The ages of Sonu and monu are in the ratio 5:7.
Assume that the age of Sonu he 5x and Monu be 7x.
9 years ago, the age of Sonu would have been twice the age of Monu.
9 years ago:
- Age of Sonu = (5x - 9) years
- Age of Monu = (7x - 9) years
As per given condition,
→ 5x - 9 = 2(7x - 9)
→ 5x - 9 = 14x - 18
→ 14x - 5x = - 9 + 18
→ 9x = 9
→ x = 1
Hence, the present age of
- Sonu = 5x = 5(1) = 5 years
- Monu = 7x = 7(1) = 7 years
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