Math, asked by mamtatyagi, 1 year ago

the ages of sonu and monu are in the ratio 7:5 ten years hence the ratio of their ages will be 9:7 find their present ages.

Answers

Answered by Anonymous
69
Ratio of the present ages of Sonu and Monu = 7:5
Let the ages be 7x and 5x
Ages after 10 years = (7x + 10) and (5x + 10)
Ratio of ages after 10 years = 9:7
⇒ (7x + 10) : (5x + 10) = 9 : 7
Product of extremes = Product of means
7(7x + 10) = 9(5x + 10)
49x + 70 = 45x + 90
49x - 45x = 90 - 70
4x = 20
x = 5
Therefore, the present ages of Sonu and Monu are (7x5) and (5x5) i.e. 35 years and 25 years.


Regards, Riyanshu.........!!❤
Answered by neeti123kn
8

HERE'S THE ANSWER

Ratio of the present ages of Sonu and Monu = 7:5

Let the ages be 7x and 5x

Ages after 10 years = (7x + 10) and (5x + 10)

Ratio of ages after 10 years = 9:7

⇒ (7x + 10) : (5x + 10) = 9 : 7

Product of extremes = Product of means

7(7x + 10) = 9(5x + 10)

49x + 70 = 45x + 90

49x - 45x = 90 - 70

4x = 20

x = 5

→→Therefore, the present ages of Sonu and Monu are (7x5) and (5x5) i.e. 35 years and 25 years.

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