The ages of sonu and Monu are in the ratio of 5:7 .if sonu were 9 years older and Monu 9 years younger,the age of Sonu would have been twice the age of Monu.find their ages
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Answered by
75
Let the diving factor be x:
so the age of Sonu will be 5x and Monu's will be 7x
Sonu's age 9 years older will be 5x-9
Monu's age 9 years younger will be 7x-9
Sonu's age will be twice that of Monu, that means Monu's age times 2 will be equal to Sonu's age.
that means 5x-9=2(7x-9)
5x-9=14x-18
14x-5x=18-9
9x=9
x=1
Sonu's age (5x) therefore is 5(1)= 5 years
Monu's age (7x) therefore is 7(1)= 7 years
so the age of Sonu will be 5x and Monu's will be 7x
Sonu's age 9 years older will be 5x-9
Monu's age 9 years younger will be 7x-9
Sonu's age will be twice that of Monu, that means Monu's age times 2 will be equal to Sonu's age.
that means 5x-9=2(7x-9)
5x-9=14x-18
14x-5x=18-9
9x=9
x=1
Sonu's age (5x) therefore is 5(1)= 5 years
Monu's age (7x) therefore is 7(1)= 7 years
Answered by
41
Step-by-step explanation:
sonu=5x
monu=7x
(5x+9)=2(7x-9)
5x+9=14x-18
18-9=14x-5x
9=9x
x=9
9
x=1
5x=5×1=5
7x=7×1=7
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