the ages of sonu and monu are in the ratio of 7.5 ten years hence the ratio of they ages will be 9.7 find their presnt ages
Answers
Step-by-step explanation:
- The ages of Sonu and Monu are in the ratio 7:5
- Ten years hence the ratio becomes 9:7
- The present ages of Sonu and Monu
According to the question :-
Let the age of Sonu be 7x and
Age of Monu be 5x
After 10 years:-
Age of Sonu = (7x + 10)
Age of Monu = (5x + 10)
But Given:-
The ratio of they ages will be 9:7
Therefore:-
(7x + 10) : (5x + 10) = 9:7
By cross multiplication
7(7x + 10) = 9(5x + 10)
》49x + 70 = 45x + 90
》 49x - 45x = 90 - 70
》 4x = 20
》 x = 20/4
》 x = 5
Present age of Sonu = 7x = 7× 5 = 35 years
Present age of Sonu = 7x = 7× 5 = 35 yearsPresent age of Monu = 5x = 5×5 = 25 years
Given :
- The ages of sonu and monu are in the ratio of 7.5 ten years hence the ratio of they ages will be 9.7 .
To Find :
- Find their present ages.
Procedure :
Let the sonu age be 7x and the monu's age to be 5x.
After 10 years :
- Age of sonu = 7x + 10
- Age of monu = 5x + 10
After 10 years the ratio of sonu's and monu's age is 7x + 10 : 5x + 10
This ratio is equal to 9 : 7
Therefore,
➨ 7x + 10 : 5x + 10 = 9 : 7
➨ 7(7x + 10) = 9(5x + 10)
➨ 49x + 70 = 45x + 90
➨ 49x - 45x = 90 - 70
➨ 4x = 20
➨ x = 20/4
➨ x = 5
Therefore,
- Sonu's age = 7x = 7 × 5 = 35 years.
- Monu's age = 5x = 5 × 5 = 25 years.