Math, asked by KRISTAN07, 5 months ago

the ages of sonu and mounti are in the ratio 7:5 10 years hence , the ratio of their ages will be 9:7 find their present ages​

Answers

Answered by chanddeepali308
0

Answer:

It is given that the ratio of the ages of Sonu and Mounti is 7:5

let the present ages of Sonu and Mounti be 7x and 5x years

After 10 years

Age of Sonu= 7x + 10 years

Age of Mounti= 5x+ 10 years

According to the question,

7x + 10/5x + 10 = 9/7

or 49x + 70 =45x + 90

or 49x - 45x = 90-70

or 4x = 20

or x = 5

present age of Sonu= 7X5= 35 years

present age of Mounti =5X5=25 years.....

Step-by-step explanation:

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Answered by UniquePrincess1234
1

It is given that the ages of Sonu and Monu is 7:5

Let the present ages of Sonu and Monu be 7x and 5x years respectively.

After ten years,

Age of Sonu = 7x+10

Age of Monu = 5x+10

According to question,

(7x+10)/(5x+10) = (9)/(7)

49x + 70 = 45x + 90

49x - 45x = 90 - 70

4x = 20

x = 20/4

x = 5

Therefore,

present ages of Sonu and monu are :-

Sonu = 7×5=35 years

Monu = 5×5 = 25 years

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