the ages of sonu and mounti are in the ratio 7:5 10 years hence , the ratio of their ages will be 9:7 find their present ages
Answers
Answer:
It is given that the ratio of the ages of Sonu and Mounti is 7:5
let the present ages of Sonu and Mounti be 7x and 5x years
After 10 years
Age of Sonu= 7x + 10 years
Age of Mounti= 5x+ 10 years
According to the question,
7x + 10/5x + 10 = 9/7
or 49x + 70 =45x + 90
or 49x - 45x = 90-70
or 4x = 20
or x = 5
present age of Sonu= 7X5= 35 years
present age of Mounti =5X5=25 years.....
Step-by-step explanation:
hope this helps
please mark me as brainlist
thanku
It is given that the ages of Sonu and Monu is 7:5
Let the present ages of Sonu and Monu be 7x and 5x years respectively.
After ten years,
Age of Sonu = 7x+10
Age of Monu = 5x+10
According to question,
(7x+10)/(5x+10) = (9)/(7)
49x + 70 = 45x + 90
49x - 45x = 90 - 70
4x = 20
x = 20/4
x = 5
Therefore,
present ages of Sonu and monu are :-
Sonu = 7×5=35 years
Monu = 5×5 = 25 years