Math, asked by deepti34197, 5 hours ago

the ages of Suman and Neelam are in ratio 3:4.4years ago their ages were in ratio 5:7.find their ages​

Answers

Answered by snehitha2
10

Answer:

Suman's age = 24 years

Neelam's age = 32 years

Step-by-step explanation:

Given :

The ages of Suman and Neelam are in the ratio 3 : 4.

4 years ago, their ages were in the ratio 5 : 7.

To find :

their ages

Solution :

Let the present age of Suman be 3x and Neelam be 4x.

4 years ago,

Suman's age = (3x – 4) years

Neelam's age = (4x – 4) years

Given their ages were in the ratio 5 : 7.

(3x – 4)/(4x – 4) = 5/7

7(3x – 4) = 5(4x – 4)

21x – 28 = 20x – 20

21x – 20x = 28 – 20

x = 8

Substituting the value of x,

Suman's age = 3(8) = 24 years

Neelam's age = 4(8) = 32 years

Answered by ItzMissKomal
2

Answer:

given ratio = 3/4

so the present age of suman be = 3x

and the present age of neelam be = 4x

now according to question,

4 years ago age of suman = 3x -4

4 years ago age of neelam = 4x -4

and now their ages ratio ( 4 years ago) become = 5/7

on comparing

3x-4/ 4x -4 = 5/7

we get

x = 8

so,

the age of suman = 24 yrs,

and the age of neelam = 32 yrs.

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