Math, asked by indra3, 1 year ago

the ages of the two persons are in the ratio 5:7. eighteen years ago their ages were in the ratio 8:13. find their present ages

Answers

Answered by resonance
35

X and y are their present age
Attachments:
Answered by pr264428
51

Answer:

50 and 70 years.

Step-by-step explanation:

In the question,

The ratio of the ages of two persons = 5:7

Ratio of their ages 18 years ago = 8:13

Now,

Present age of first person = 5x

Present age of second person = 7x

So,

Age 18 years ago = 5x - 18

Age 18 years ago of second person = 7x - 18

So,

\frac{5x-18}{7x-18}=\frac{8}{13}\\65x-234=56x-144\\9x=90\\x=10

Therefore, the Present age of first person = 5 x 10 = 50

Present age of another person = 7 x 10 = 70

Hence, the present ages of the people are 50 and 70 years.

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