The ages of three boys add up to 76. If the ratio of their ages 4 years ago is 4:5:7, what is the current age of the oldest
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Answered by
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Answer:
32 years
Step-by-step explanation:
Given
Sum of their ages before 4 years will be 64(76-12)
Acc to given data
4x + 5x + 7x = 64
16x= 64
x= 4
Age of the eldest one before 4 years is 4*7= 28 yrs
His age now = 28+4= 32 yrs
Answered by
0
Step-by-step explanation:
Let 4 be 4x , 5 be 5x and 7 be 7x
4x + 5x +7x = 76
= 16x = 76
= x =76/16
=4.75
Then multiply 4 , 5 , 7 by 4.75
The answers you get is the actual answer
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