The ages of three friends are consecutive integers. If their three consecutive ages have a sum of 192, what is the age of the oldest friend?
Answers
Answered by
3
Answer:
63,64,65
let middle one be of age x
younger is x-1
and olde is x+1
sum of 3 is 3x = 192
so x is 64
others are 63 and 65
Answered by
1
Answer:
x
x+1
x+2
3x+3=192
x = 63
63+64+65=192
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