Question

The ages of three friends are consecutive integers. If their three consecutive ages have a sum of 192, what is the age of the oldest friend?

Answer 1

Answer:

• Age of oldest friend = 65 years

Explanation:

Let, ages of three friends be,

x , x + 1 , x + 2

(These three are consecutive integers.)

Where, x is the age of the youngest friend.

x + 1 is the age of the middle age friend. and

x + 2 is the age of oldest friend.

According to the question,

→ Sum of ages of all friends = 192

so,

→ ( x ) + ( x + 1 ) + ( x + 2 ) = 192

→ x + x + 1 + x + 2 = 192

→ 3 x + 3 = 192

→ 3 x = 192 - 3

→ 3 x = 189

→ x = 189/3

→ x = 63

Therefore,

Age of the oldest friend would be,

→ x + 2 = 63 + 2 = 65 yrs

Hence,

• Age of oldest friend would be 65 years.

Answer 2

Step-by-step explanation:

Required answer:-

Let

the age of middle age friend=x

${:}\mapsto$The age of the youngest friend =(x-1)

${:}\mapsto$The age of the oldest friend =(x+1)

• Now

According to question

${:}\mapsto$The sum of their ages=192

${:}\mapsto$$x+(x+1)+(x-1)=192$

${:}\mapsto$$x+x+{\cancel{1}}+x{\cancel {-1}}=192$

${:}\mapsto$$3x=192$

${:}\mapsto$$x={\dfrac {192}{3}}$

${:}\longmapsto$${\underline{\boxed{\bf {x=64}}}}$

hence

The age of oldest friend =x+1=64+1=65years