The ages of three men are in the ratio 3:4:5. If the difference between the ages of the oldest and youngest is 18 years, find the sum of the ages of the three men.
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Let the ages be 3x, 4x and 5x years.
5x - 3x = 18
2x = 18
x = 9
5x + 4x + 3x
12x
12 × 9
108
The sum of their ages is 108 years.
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