Question

The ages of three men are in the ratio of 3:4:5. If the difference between the ages of the oldest and the youngest is 18 years, find the sum of the ages of the three men.

Answer 1

Answer:

108

Step-by-step explanation:

Ratio of ages = 3:4:5

Difference between oldest and youngest = 18

∴Sum of their ages

3x + 4x + 5x = sum of their ages

5x (oldest) - 3x (youngest) = 18

2x = 18

x = 9

age of youngest man = 9*3 = 27

age of middle man = 9*4 = 36

age of oldest man = 9*5 = 45

sum of their ages = 27 + 36 + 45 = 108

Hope this helps!!!!!

Answer 2

Answer:

let their ages be 3x 4x 5x respectively

Now 5x-3x=18

2x=18

x=9

3x=3×9=27

4x=4×9=36

5x=5×9=45

3x+4x+5x=27+36+45

=108