the ages of two boys A and B are 6 years 8 months and 7 years 4 months respectively. Divide Rs 3,150 in the ratio of their ages.
Answers
Answered by
205
A = 6 years 8 months = 6 8/12 years = 6 2/3 years = 20/3 years
B = 7 years 4 months = 7 4/12 years = 7 1/3 years = 22/3 years
A : B
= 20/3 : 22/3 (multiply with 3)
= 20 : 22
= 10 : 11
The A portion of the money
= 10/(10 + 11) × 3,150
= 10/21 × 3,150
= 1,500
The B portion of the money
= 11/21 × 3,150
= 1,650
B = 7 years 4 months = 7 4/12 years = 7 1/3 years = 22/3 years
A : B
= 20/3 : 22/3 (multiply with 3)
= 20 : 22
= 10 : 11
The A portion of the money
= 10/(10 + 11) × 3,150
= 10/21 × 3,150
= 1,500
The B portion of the money
= 11/21 × 3,150
= 1,650
Answered by
37
Answer:
The age of A is 6years 8/12months.
so the age of A will be 6 years 2/3 months and the age of B is 7years 4/12months.
so the age of B will be 7years 1/3months.
The age of
A=20/3
B=22/3
(multiplying both a&b with 1/3)
A=20
B=22
The ratio of A and B will be
20/22 = 10/11
Ratio to their ages =
part A= 10/(10+11)×3150
=10/21×3150=10×150=1500
part B=11/(10+11)×3150
=11/21×3150
=11×150
=1650
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