the ages of two friends ani and Biju differ by 3 years and his father Dharam is twice as old as ani and Biju as twice as old as his sister Cathy the ages of Cathy and dharam differ by 30 years. Find the ages of Ani and biju
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Let the ages of Ani be A
Let the age of Biju be B
Hence, the age of Dharam = 2 x A = 2A yrs.
The age of Biju sister Ani B/2 yrs
As per the given conditions will solve
Case (i)
When Ani is older than that of Biju
A – B = 3 – – – – – – – – (1) {older by 3 years}
2A−B/2 = 30
4A – B = 60 – – – – – – – – – – – (2)
By subtracting the equations (1) and (2) we get,
3A = 60 – 3 = 57
A = 57/3 = 19
The age of Ani = 19 yrs
The age of Biju is 19 – 3 = 16 yrs.
Case (ii)
When Biju is older than Ani,
B – A = 3 – – – – – – – – – (1) {older by 3 years}
2A − B/2 = 30
4A – B = 60 – – – – – – – – – (2)
Adding the equation (1) and (2) we get,
3A = 63
A = 21
Answer
The age of Ani is 21 yrs
The age of Biju is 21 + 3 = 24 yrs.
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