Question

the ages of two friends Ani and Biju differ by 3 years. Ani's father Dharam is twice old as Ani and Biju as twice as old as his sister Cathy. The age of Cathy and Dharam differ by 30 years. Find the age of Ani and Biju.

Answer 1

The difference btw ages of biju and anil is 3 yrs. Let the ages be X and Y ..

Ani’s father’s age will be 30 years more than that of Cathy’s age,
∴ Dharam s age be 2X yrs and
bijus sister cathys age be Y / 2 yrs 
And assume that biju is 3 yr older than ani and ani is 3 yr older than biju 

:When Ani is older than Biju by 3 years,

x − y = 3 …...............(i)

2x – y / 2 = 30

4x − y = 60 …...............(ii)

Subtracting (i) from (ii), we obtain

3x = 60 − 3 = 57

x = 57 / 3 = 19

Therefore, age of Ani = 19 years

And age of Biju = 19 − 3 = 16 years

Case (ii) :When Biju is older than Ani,

y − x = 3 …........ (I)

2x – y / 2 = 30

4x − y = 60 …...............(ii)

Adding (i) and (ii), we obtain

3x = 63

x = 21

Therefore, age of Ani = 21 years

And age of Biju = 21 + 3 = 24 years. 

HOPE THIS ANS IS USEFUL .....

Answer 2

hi...dear...
here is your answer
Let the age of Ani and Biju be x and y years respectively.
since.
age of Ani’s father, Dharam = 2 × x = 2x years
age of Biju’s sister Cathy  = y / 2 years

Case (i) :When Ani is older than Biju by 3 years,

x − y = 3 …...............(i)

2x – y / 2 = 30

4x − y = 60 …...............(ii)

Subtracting (i) from (ii)

3x = 60 − 3 = 57

x = 57 / 3 = 19

so, age of Ani = 19 years
..age of Biju = 19 − 3 = 16 years

Case (ii) :When Biju is older than Ani,

y − x = 3 …........ (I)

2x – y / 2 = 30

4x − y = 60 …...............(ii)

Adding (i) and (ii),

3x = 63

x = 21
, age of Ani = 21 years
age of Biju = 21 + 3 = 24 years...
hope this helps you....!!