Question

The ages of two friends ani and biju differ by 3 years. Anis father dharam is twice as oldas ani and biju is twice as old as his sister cathy. The ages of cathy and dharam differby 30 years. Find the ages of ani and biju.

Answer 1

Step-by-step explanation:

let ani age be X and Biju age be Y

according to question x -y = 3 (1) and Y-X=3 (2)

again A/q dharma age=2x

Cathy age=Y/2

A/Q 2X-Y/2=30

4x-y=60 (3)

after solving 1 and 3

X=19 years

Y=16 years

after solving 2 and 3

X=21 years

Y= 24 years

ages are respectively (19,16) and(21,24)

Answer 2

Answer:

$\huge{\mathcal{\underline{\green{Answer}}}}$

Let the ages of Ani be A

Let the age of Biju be B

Hence, the age of Dharam = 2 x A = 2A yrs.

The age of Biju sister Ani B/2 yrs

As per the given conditions will solve

Case (i)

When Ani is older than that of Biju

A – B = 3 – – – – – – – – (1) {older by 3 years}

2A−B/2 = 30

4A – B = 60 – – – – – – – – – – – (2)

By subtracting the equations (1) and (2) we get,

3A = 60 – 3 = 57

A = 57/3 = 19

The age of Ani = 19 yrs

The age of Biju is 19 – 3 = 16 yrs.

Case (ii)

When Biju is older than Ani,

B – A = 3 – – – – – – – – – (1) {older by 3 years}

2A − B/2 = 30

4A – B = 60 – – – – – – – – – (2)

Adding the equation (1) and (2) we get,

3A = 63

A = 21

Answer

The age of Ani is 21 yrs

The age of Biju is 21 + 3 = 24 yrs.