Question

The ages of two friends are in the ratio 4:5. Five years ago, the ratio of their was 3 : 4. find their present age
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Answer 1

Answer:

$let \: first \: friend \: be \: x \: \\ let \: second \: friend \: be \: y \\ 4x + 5y \\ after \: five \: years.3x + 4y \\ 4x + 5y = 5(3x + 4y) \\ 4x + 5y = 15x + 20y \\ 4x - 15x = 20y - y \\ - 11x = 19y \\ x \div y = 19 \div - 11$

hope u understand