The ages of two girls are in the ratio 5 : 7. Eight years ago their ages were in the ratio 7 : 13. Find their present ages.
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Let their present ages be 5x &7x
So eight years back they were 5x-8 years and 7x-8 years old
Therefore 5x-8=7y & 7x-8=13y
5x-7y=8 ..........(1)
7x-13y=8..........(2)
(1)×7 = 35x-49y=56........(3)
(2)×5=35x-65y=40........(4)
Subtract (4) from (3)
We get y=1
Now for x
5x-8=7
5x=15
So,x=3
Their present ages are 5x=15 &7x=21
Let their present ages be 5x &7x
So eight years back they were 5x-8 years and 7x-8 years old
Therefore 5x-8=7y & 7x-8=13y
5x-7y=8 ..........(1)
7x-13y=8..........(2)
(1)×7 = 35x-49y=56........(3)
(2)×5=35x-65y=40........(4)
Subtract (4) from (3)
We get y=1
Now for x
5x-8=7
5x=15
So,x=3
Their present ages are 5x=15 &7x=21
Answered by
2
Answer:15 and 21
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