The ages of two girls are in the ratio 5 : 7. Eight years ago their ages were in the ratio 7 : 13. Find their present
ages
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Answer:
let the common multiple be x
so, 5x , 7x
8years ago ages are
5x - 8
7X - 8
by the problem
5x - 8 / 7x - 8 = 7/13
7(7x - 8 ) = 13 ( 5x - 8 )
49x - 56. = 65x - 104
-56 + 104 = 65x - 49x
48 = 16x
X = 48/16
X = 3
so present age of girls = 5*3 = 15
= 7*3 = 21.
Answered by
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Answer:
The present ages of girls are 15 & 21
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