Question

The ages of two girls are in the ratio 5 : 7. Eight years ago their ages were in the ratio 7 : 13. Find their present

ages​

Answer 1

Answer:

let the common multiple be x

so, 5x , 7x

8years ago ages are

5x - 8

7X - 8

by the problem

5x - 8 / 7x - 8 = 7/13

7(7x - 8 ) = 13 ( 5x - 8 )

49x - 56. = 65x - 104

-56 + 104 = 65x - 49x

48 = 16x

X = 48/16

X = 3

so present age of girls = 5*3 = 15

= 7*3 = 21.

Answer 2

Answer:

The present ages of girls are 15 & 21

Step-by-Step Explanation: