Question

the ages of two girls are in the ratio 5 ratio 7 8 years ago their ages were in the ratio 7 ratio 13 find their present ages​

Answer 1

Answer:

(x/y)=5/7

and X=(5/7)y

and 8 years ago

(x-8)/(y-8)=7/13

so from second equation

13x - 104= 7y -56

13x -7y=48 (putting x=(5/7)y

13(5/7)y - 7y= 48

65y-49y=336

16y=336

y=21

and X is =15

as above ratio

Answer 2

Answer:

(x/y)=5/7&x=(5/7)y

8 yrs ago

(x-8)/(y-8)=7/13

2nd eq.

13x-104=7y-56

13x-7y=48

13(5/7)y-7y=48

65y-49y=336

16y=336

y=21

x=15

mark as BRAINLIEST ❤️❤️❤️

xiexie!!!