Question

The ages of two girls are in the ratio5:7.Eight uears ago their ages were in the ratio7:13.Find their present ages

Answer 1

Answer:

Step-by-step explanation:

Ratio = 5:7

Let the age of 1st girl be 5x

2nd!= 7x

8 years ago

A to q

5x - 8 : 7x - 8 = 7:13

On cross multiply

13(5x-8) = 7(7x-8)

65 x - 104 = 49x - 56

65x - 49x = -56 + 104

16x = 48

X = 48/16 = 3

Present ages =

1st girl, 5x = 5×3 = 15

2nd girl! 7x = 7×3 = 21

Hope it helps uh

Plz mark as brainliest