Math, asked by moushmisaha310, 8 months ago

The ages of two person are in the ratio 5:7 . Eighteen years ago their ages were in the ratio 8:13 . Find their present ages?

Answers

Answered by pranjal512

Answer:

Let the present ages of two persons be 5x and 7x years Age of two persons 18 years ago are (5x – 18) and (7x – 18) years Given (5x – 18)/(7x – 18) = 8/13 13(5x – 18) = 8(7x – 18) 65x – 234 = 56x – 144 9x = 90 Therefore, x = 10 Thus age of the two persons are 50 and 70 years

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