Question

The ages of two person differ by 20 yr. If 5 yr ago, the elder one be 5 time as old as the younger one, their present ages are​

Answer 1

30 and 10 are the required present ages of two person.

CONSIDER:

• Let the present age of two persons be 'x' and 'y'.
• Let x be elder to y.
• Let x-5 be the age of x before 5 years.
• Let y-5 be the age of y before 5 years.

GIVEN:

• The ages of two person differ by 20 years.
• x - y = 20

• 5 years ago, the elder one be 5 time as old as the younger one.
• x-5 = 5 (y-5)

TO FIND:

The present ages of two person x and y.

SOLUTION:

At present,

x-y = 20

-y = 20 - x

y = x - 20

Substitute y = x - 20 in x-5 = 5 (y-5)

x - 5 = 5(x- 20 -5)

x-5 = 5(x-25)

x-5 = 5x - 125

5x-x = 125-5

4x = 120

x = 120/4

x =60/2

x = 30

THE PRESENT AGE OF X IS 30.

Substitute x= 30 in x- y = 20

30-y = 20

30-20 = y

y = 10

THE PRESENT AGE OF Y IS 10

ANSWER:

• The present age of x is 30. He is 30 years old now. Before 5 years his age is 30-5= 25.

• The present age of y is 10 . He is 10 years old now. Before 5 years , his age is 10-5= 5.

Answer 2

Age of elder one =30 years

Age of younger one =10 years

Step-by-step explanation:

Let the age of elder one be X years

then the age of younger one be X-20 years

since their age diffrence is 20 years

now five years ago their ages would be

Elders age X-5 years

and youngers age X-20-5=X-25 years

now elders age is 5 times the youngers age in five years ago

=>X-5=5(X-25)

=>X-5=5X-125

=>125-5=5X-X

=>120=4x

=>X=120/4

=>X=30 years

Elder's present age=30 years

Younger's present age=30-20=10 years