Question

The ages of two persons are in the ratio 5:7 . Eighteen years ago their ages were in the ratio 8:13. find the present age

Answer 1

Answer:

50 years and 70 years

Step-by-step explanation:

Let the age of first person be 5x and second person be 7x.

18 years ago,

First person = (5x - 18)

Second person = (7x - 18)

$\frac{5x-18}{7x-18}=\frac{8}{13}\\ \\13(5x-18)=8(7x-18)\\\\65x-234=56x-144\\\\65x-56x= -144+234\\\\9x=90\\\\x= \frac{90}{9}\\\\\boxed{\bf x=10}$

Age of first person = 5x = 50 years

Age of second years = 7x = 70 years.

_______________________

Answer 2

HERE IS UR ANS :»»»»»»

let the ages of two person be 7x and 5x

before 18 years their age is( 7x -18)& (5x-17)

then ATQ the equation Will be

(7x - 18)/(5x-18)=8/13(it is the present ages)

13(5x-18)=8(7x-18) (cross multiplication)

65x -234=56x-144

65x-56x =-144+234(transportation)

9x=90

x=10

now we will put the values of x

5*10=50

7*10=70

hope it helped u

pls follow me..