Question

The ages of two persons are in the ratio of 5:7:18 years ago their ages in the ratio of 8:13. What are their present ages?
a) 45 years: 65 years
b) 50 years:70 years
c) 50 years: 60 years
d) 45 years: 63 years​

Answer 1

Answer:

Let the present ages of two persons be 5x and 7x years Age of two persons 18 years ago are (5x – 18) and (7x – 18) years Given (5x – 18)/(7x – 18) = 8/13 13(5x – 18) = 8(7x – 18) 65x – 234 = 56x – 144 9x = 90 Therefore, x = 10 Thus age of the two persons are 50 and 70 years.

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Answer 2

Let the present ages of two persons be 5x and 7x years Age of two persons 18 years ago are (5x – 18) and (7x – 18) years Given (5x – 18)/(7x – 18) = 8/13 13(5x – 18) = 8(7x – 18) 65x – 234 = 56x – 144 9x = 90 Therefore, x = 10 Thus age of the two persons are 50 and 70 years.

50 years:70 years

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