Math, asked by vallemrahul6341, 9 days ago

The ages of two persons are in theratio 5:7. Eighteen years ago theirages were in the ratio of 8:13, theirpresent ages (in years) are :

Answers

Answered by Itzheartcracer
5

Given :-

The ages of two persons are in the ratio 5:7. Eighteen years ago their ages were in the ratio of 8:13

To Find :-

Present ages

Solution :-

Let their present ages be 5x and 7x

18 years ago

5x - 18/7x - 18 = 8/13

13(5x - 18) = 8(7x - 18)

65x - 234 = 56x - 144

65x - 56x = -144 + 234

9x = 90

x = 90/9

x = 10

Age of Person 1 = 5x = 5(10) = 50 years

Age of Person 2 = 7x = 7(10) = 70 years

Answered by hiteshwar009
2

Answer:

Present ages 50 and 70

Step-by-step explanation:

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