Math, asked by 1704663, 3 months ago

The ages of two persons differ by 1616 years. 66 years ago, the elder one was 33 times as old as the younger one. What is the present age of the elder
person?
(A) 20
(B) 30
PIC) 40
(D) 10

Answers

Answered by kavitha2057
0

Answer:

Correct option is

B

14 years and 30 years

Let the age of younger person be x years.

∴ Age of elder person =16+x years$$

6 years ago,

Age of younger person =(x−6) years

Age of elder person =(16+x−6) years

=(10+x) years

According to question, x+10=3(x−6)

⇒x+10=3x−18⇒2x=28

⇒x=14

∴ Age of younger person =14 years

Age of elder person =(14+16) years

=30 yeras

Similar questions