the ages of two persons differ by 20 years.if 5 years ago, the elder one be 5 times as old as the younger one, their present ages are respectively (in years).
Answers
Answered by
1
Answer:
Option D
Step-by-step explanation:
Let their ages be x and (x + 20) years.
5 (x - 5) = (x + 20 - 5) or 4x = 40 or x = 10.
Their present ages are 30 years and 10 years
Answered by
2
Answer:
Age of elder one =30 years
Age of younger one =10 years
Step-by-step explanation:
Let the age of elder one be X years
then the age of younger one be X-20 years
since their age diffrence is 20 years
now five years ago their ages would be
Elders age X-5 years
and youngers age X-20-5=X-25 years
now elders age is 5 times the youngers age in five years ago
=>X-5=5(X-25)
=>X-5=5X-125
=>125-5=5X-X
=>120=4x
=>X=120/4
=>X=30 years
Elder's present age=30 years
Younger's present age=30-20=10 years
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