Math, asked by kumaridavidadi, 4 months ago

the ages of two persons differ by 20 years.if 5 years ago, the elder one be 5 times as old as the younger one, their present ages are respectively (in years).​

Answers

Answered by stefaniegeorge253
1

Answer:

Option D

Step-by-step explanation:

Let their ages be x and (x + 20) years.

5 (x - 5) = (x + 20 - 5) or 4x = 40 or x = 10.

Their present ages are 30 years and 10 years

Answered by Salmonpanna2022
2

Answer:

Age of elder one =30 years

Age of younger one =10 years

Step-by-step explanation:

Let the age of elder one be X years

then the age of younger one be X-20 years

since their age diffrence is 20 years

now five years ago their ages would be

Elders age X-5 years

and youngers age X-20-5=X-25 years

now elders age is 5 times the youngers age in five years ago

=>X-5=5(X-25)

=>X-5=5X-125

=>125-5=5X-X

=>120=4x

=>X=120/4

=>X=30 years

Elder's present age=30 years

Younger's present age=30-20=10 years

Similar questions