Question

The ages of two persons differ by 20 years.if 5 years ago the elder one be 5 times as old as the younger one ,their present ages are?

Answer 1

According to question
Present ages of two persons x and 20+x
Now (20+x-5) = 5(x-5)
Solve it, x= 10
So their present ages 10, 30

Answer 2

Answer:

Age of elder one =30 years

Age of younger one =10 years

Step-by-step explanation:

Let the age of elder one be X years

then the age of younger one be X-20 years

since their age diffrence is 20 years

now five years ago their ages would be

Elders age X-5 years

and youngers age X-20-5=X-25 years

now elders age is 5 times the youngers age in five years ago

=>X-5=5(X-25)

=>X-5=5X-125

=>125-5=5X-X

=>120=4x

=>X=120/4

=>X=30 years

Elder's present age=30 years

Younger's present age=30-20=10 years